We all know that the hour hand and the minute
hand on a clock travel at different speeds .However, there are certain occasion
when they are exactly opposite each other. Can you give a simple formula for
calculating the times of these occasions?
Answer: Here is the formula that gives the
minutes past twelve to which the hour hand points when the minute hand is
exactly thirty minutes ahead.
Minutes Past twelve Y= 30/11[(n-1) 2+1]
Where n is the next hour _
Let’s take the case of at what time between
4 and 5 will the hands be opposite each other? (n=5).
Y= 3/11 × 9=270/11 + 246/11.
I.e. the hour hand will be 24 6/11 minutes
past 4. The formula may be derived from the following: If X is distance moved
by the minute hand y is the distance moved by hour hand.
Then X-Y = 30
First time the hands move round X= 12 Y
Second time the hands move round X=12 Y- 5
Third time the hands move round X= 12 Y-10 etc
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