What is the smallest number which when divided by 10 leaves
a remainder of 9, when divided by 9 leaves a remainder of 8, when divided by 8
leaves a remainder of 7 and so on until when divided by 2 leaves a remainder of
1?
Answer: The
number must be in the form:
N = Rk -1 , where R
is the least common multiple of 2,3,4,5,6,7,8
and 9.
K= 1,2,3,4,………
R = 2520
N = 2520 -1 ; N= 2519
