A Problem of Candy Bars

          Recently I attended a birthday party. All the children in the party were given candy bars. All the children got three candy bars each except the child sitting in the end. She got only two candy bars there would have been eight candy bars remaining. How many candy bars were there altogether to begin with?

Answer:         If there were x children at the party then the two ways of distributing the candy can be represented by these two expressions:

3(x-1) +2 and 2x +8

3x -3+2 = 2x +8

Or x=9

The number of candy for distribution = 2x9+8 =26