A friend of mine in London has a very nice cellar. He has two
large barrels in the cellar. The larger barrel is mostly empty. But the smaller
barrel is only 5/6th full of wine while it can hold 536 litres.
Supposing he empties the smaller barrel and fills the bigger
barrel to find that the wine fills only 4/9ths of it, how much wine would the
larger barrel hold when full?
Answer: 630 Litres: Let us assume x is the capacity of
the second barrel.
Then our equation will be:
5/6 x 336 = 4/9 x X
X = 5 x 336 x 9 / 6x 1x 4 =630
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