Division of 45

          Can you divide the number 45 into four parts such that when 2 is added to the first part, 2 is subtracted from the second part, 2 is multiplied by the third part, and the fourth part is divided by 2. All the four results should be the same number.

Answer:     8, 12, 5, 20

A+B+C+ D = 45

A+2 = B-2 = 2C = D/2

A = B -4; C = B-2 /2; D= 2(B-2)

B -4 +B -2/2 +2(B-2) = 45

B = 12

A = 8

 C= 5

D = 20

Thus: 12 -2 = 8 +2 = 5x2 =20/2 =10